A proof for the Stationary Earth

[HMS_Beagle]

Beagle is trolling, that's why.

JM

OK, the evidence now indicate JM isn't trolling, he's just really really stupid.

[JohnMartin]

What is the wind equivalent of this force John. What does it equate to in miles per hour (or kilometers per hour if you prefer). not the total velocity change over the entire journey, but moment by moment - the actual force the pilot would encounter as he flies the plane?

You claim it is 'not' there. But how much of breeze is required for the pilot to notice it over the other winds and turbulance he encounters flying the plane? And is it big enough to notice? If it is too small to notice, then how do you know it is not happening?


Jim

If its too small to measure, how do you know it is happening. If it cannot be measured, then the force remains only hypothetical within the rotating earth model.

JM

[lilpixieofterror]

No John. An average acceleration of 14.38m/s^2 operating over 3.3 hours would produce a velocity differential of ...

(1) a = 14.38 m/s^2
(2) v = 14.38*t m/s
(3) d = 7.19*t^2 m

So the final velocity shift associated with the acceleration you have described here would be 14.38 m/s^2 *(3.3*3600) s = 277,000 m/s = 277 km/s * 3600 s/h = 997,200 km/h

OOOOPS!!! Wow! 997,200 km/h is a whole heck of a lot faster than 277 km/h. I wonder where you went wrong? Well, let's see ...

To find actual acceleration required to produce a velocity of 277 km/h after 3.3 hours first lets get the velocity in meters per second (since we generally like to express acceleration in m/s^2)

277 km/h*1000m/km = 277,000 m/h * 1/3600 h/s = 23.32 m/s

Now from our basic 3 equations of motion listed above

v = a*t

so that means to find 'a', we set up using our value for v and t (in meters and seconds)

23.32 m/s = a m/s^2 * (3.3 * 3600) s

Now we solve for a:

a= 23.32/3.3*3600 = .0019 (all the units just cancel out and we have a simple constant)



Now what velocity breeze would that feel like? Well, velocity is d/t, and so to get an effective velocity, we need the distance that change in velocity will move the air in 1 second, and that is 1/2at^2 or (since t=1) .00095m.

So each second the change in atmospheric velocity would feel like a 'breeze' of .00095 m/s, or about .0034km/h

When is the last time you noticed a breeze of 3.4 thousandths of a km/h?


Jim

ETA: to be clear - that is the W-E breeze a supersonic F-18 Hornet would feel at full speed and due north. How much time does anyone suppose a pilot spends worrying about breezes of .0034 km/h while they are rocketing across the landscape at nearly 2 times the speed of sound?

Considering that the USAF refuels dozens of aircraft every single day, JM is just showing he doesn't know what he's talking about. I mean, if we follow his logic, air refueling should be impossible.

[JohnMartin]

Yes, I forgot about magic Eather flow. The stuff that magically produces fake evidence for a rotating earth, but yet is unobserable and undetectable by anything. Of course, the much easier explanation that the earth really is rotating and that you're a nutcase trying desperately to defend nonsense is automatically discounted.

Mindless rambling.

JM

[lilpixieofterror]

It seems I've been corrected. I've muddled up the units.

F = 29,932 x 0.0019 = 56.87 N

Pressure on Hornet = 56.87/(38) = 1.50 Pa.

The pressure difference on the Hornet may be measured if the plane flies S-N, then turns back N-S.

JM

So JM, how does mid air refueling work, in order to keep both aircraft from being knocked out of the sky?

[lilpixieofterror]

Mindless rambling.

JM

AKA, most of your post. How can magic eather flow produce all the evidence for a rotating earth, but be unable to be detected in any way?

[HMS_Beagle]

Considering that the USAF refuels dozens of aircraft every single day, JM is just showing he doesn't know what he's talking about. I mean, if we follow his logic, air refueling should be impossible.

I wonder why Moonbat thinks aircraft have wings? According to him there's no such thing as gravity so there's no need to provide lift to overcome it.

[JohnMartin]

AKA, most of your post. How can magic eather flow produce all the evidence for a rotating earth, but be unable to be detected in any way?

Why bother engaging with mindless rambling?

JM

[JohnMartin]

I wonder why Moonbat thinks aircraft have wings? According to him there's no such thing as gravity so there's no need to provide lift to overcome it.

I wonder why Beagle cannot lie straight in bed.

JM

[DesertBerean]

hmmm...and is there no fiction used in NM? I really am curious, honest.

Let me rephrase... why should I believe you that there is no such fiction in NM? remember I'm no expert in this field.

[HMS_Beagle]

Why bother engaging with mindless rambling?

I know, we really shouldn't be engaging with dullards like you but it's entertaining waiting for your next really stupid excuse.

Hey Moonbat, when you accidentally knock a cup off your kitchen counter what force makes it fall straight down to the floor?

[oxmixmudd]

If its too small to measure, how do you know it is happening. If it cannot be measured, then the force remains only hypothetical within the rotating earth model.

JM

You've tried to make out as if this force was something that should be obvious, something that should affect the flight plans of airplanes, something pilots should have to take into account when the plan their flights. I've shown you in the calculations you acknowledge as a correction the effect itself is so small as to be virtually invisible in terms of its effect in the normal every day operations of aircraft. The fact is the systems in place are designed to get the aircraft where it needs to be in spite of a myriad of potential distractions and influences that could take it off course. It's just that this particular component is so small that it just isn't anything to worry about in the grand scheme of things.

That says nothing about if it exists or if it could be measured if one wanted to measure it.

But given the variability of the weather, I seriously doubt it would be easy to measure on a typical aircraft of any type. Perhaps a massive blimp? I don't really know what it would take to measure the effect on an aircraft going N-S. But we can see its effects as it spins up hurricanes or creates noreasters. There the effect is magnified over hundreds of miles and large masses of clouds and air from the surface to many 10's of thousands of feet in altitude.

There are also the trade winds themselves.

What can be expected from the effect is well documented, well researched. We know a lot about it, and the effects are basically as expected for a rotating Earth.

But John - you don't care about any of these facts. In fact, if you were to be convinced by any or all of us, John Martin just disappears into obscurity - just another one of the boring, moderately intelligent members of humanity whose life goes virtually unnoticed.

But as John Martin Geocentrist. Well, you are known after all. And as they say, any publicity is good publicity. So - here's to you finding a way to some measure of fame in the world. More people know your name than mine after all. So there you go.



Jim

[DesertBerean]

Which means there must be an air pressure on one side of the jet, that is not on the other side of the jet. This air pressure is never measured, nor used in design of the jet. You think otherwise? Prove me wrong. Wind tunnels for models only have wind acting from front to back and never to the side in imitating this rotating atmosphere model which you espouse.

JM

[DesertBerean]

Why bother engaging with mindless rambling?

JM

JohnMartin...you are aware, are you not, that LPOT works on military planes?

[JohnMartin]

You've tried to make out as if this force was something that should be obvious, something that should affect the flight plans of airplanes, something pilots should have to take into account when the plan their flights. I've shown you in the calculations you acknowledge as a correction the effect itself is so small as to be virtually invisible in terms of its effect in the normal every day operations of aircraft. The fact is the systems in place are designed to get the aircraft where it needs to be in spite of a myriad of potential distractions and influences that could take it off course. It's just that this particular component is so small that it just isn't anything to worry about in the grand scheme of things.

That says nothing about if it exists or if it could be measured if one wanted to measure it.

But given the variability of the weather, I seriously doubt it would be easy to measure on a typical aircraft of any type. Perhaps a massive blimp? I don't really know what it would take to measure the effect on an aircraft going N-S. But we can see its effects as it spins up hurricanes or creates noreasters. There the effect is magnified over hundreds of miles and large masses of clouds and air from the surface to many 10's of thousands of feet in altitude.

There are also the trade winds themselves.

What can be expected from the effect is well documented, well researched. We know a lot about it, and the effects are basically as expected for a rotating Earth.

Jim

The small pressure effect consistent with the rotating earth model may not exist because you have admitted that it has never been measured. The rotating earth theory remains untested in this respect. The lack of evidence for pressure on the Hornet is consistent with a stationary earth.

JM